main (int argc, char const *argv[]){
char *p;
p = &argv[1][0];
int a = strlen(argv[1]);
while (a >= 0){
printf("%c", *(p+a));
a--;
}
printf("\n");
}


Less geek, but still working

@benjamin
Pointers are so cool! I just wrote this code today morning, without looking at your Yes, you were right

#include <stdio.h>
#include <string.h>
int main (int argc, char *argv[]){
if(!argv[1]) return 0;
char *p = argv[1] + strlen(argv[1]);
while(p--!=argv[1]){
printf("%c",*p);
};
printf("\n");
}


#include
#include

int main (int argc, char** argv)
{
if (argc != 2)
return 0;

char* c = argv[1] + strlen(argv[1]);

while (c-- != argv[1])
printf("%c", *c);

printf("\n");
}

* ROFL *

*LOL*